SOLUTION: how can I write -2x^2+12x+12 in standard form?

Algebra.Com
Question 675306: how can I write -2x^2+12x+12 in standard form?
Answer by khurshidi(7)   (Show Source): You can put this solution on YOUR website!
If the question is -2x^2+12x+12=0
Then you can take '-2' as common from the equation
i.e.
-2(x^2-6x-6)=0
-2 will go to the right hand side in the denominator of zero and will become zero,
so the equation will become
x^2 - 6x - 6 = 0
or x^2 + (-6)x + (-6) = 0
This is the standard form of quadratic equation.

RELATED QUESTIONS

how do you write the quadratic equation: y=-2x^2-12x+11 in standard... (answered by solver91311)
how can I write the following linear equation : 2x=4-y in standard... (answered by josgarithmetic)
Find the product. Write the resulting polynomial in standard form. (3x-2)^2 So in order... (answered by Fombitz)
Write y=2x^2+12x+14 in vertex... (answered by jim_thompson5910)
write in vertex form -2x^2-12x-y-21=... (answered by solver91311)
Write y= 2x^2 - 12x + 16 in vertex... (answered by MathLover1,ikleyn)
How can I write these coordinates, (2,-3) and (-3,7) in slope intercept form, standard... (answered by rfer)
Through (3,-9) and parallel to 2x+3y=-12. how do i write this in standard form... (answered by scott8148)
write in "y=...."form... (answered by blfaust,rahman)