Hi,

2x³+6x²-20x= 2x (x²+3x-10)= 2x(x+5)(x-2)

2x(x+5)(x-2)=0 

  2x = 0   x = 0

0r (x+5)= 0   x = -5

0r (x-2)=0    x = 2 

solution set {-5, 0, 2} is correct.  Good work! 

RELATED QUESTIONS

{{{x(2x^2+9x-56)(3x+10)=0}}}
I did this:
(2x^3+9x^2-56x)(3x+10)=0... (answered by Alan3354)

Please help me solve this problem step by step.  I have spent more than 3 hours between 2  (answered by Alan3354)

simplify (30x^2 + 20x -10) / -5.  Is the correct solution -2(3x^2 + 2x... (answered by MathLover1,josgarithmetic,MathTherapy)

please help me solve

1) 6x^2+24x=2x^2-36

2) 3x^2-17x+20=0
for this one i got... (answered by stanbon)

Hello.
I recently got this question and I would really appreciate it if someone could... (answered by ewatrrr)

I think I solved this correctly, but just wanted to check:

9y+3x=18; -3y-x=-6... (answered by Alan3354,rothauserc)

solve for x: -4(x-2)+4=6(x-2)-7x                 
 x=9

solve for x: 2(x+1)-3x=3(3+2x)  (answered by scott8148)

i need a little help to make sure i am doing this right.

Solve: 2x-5=(the square root... (answered by jim_thompson5910)

The question is to show a solution set

{{{highlight_green(2/( 3 + x) + 4 / ( 2x + 2 )... (answered by josgarithmetic,MathTherapy)