SOLUTION: You toss a ball from 5 feet. The ball's velocity is 30 feet per second. You catch the ball at 6 feet. How long is the ball in the air?

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Question 670641: You toss a ball from 5 feet. The ball's velocity is 30 feet per second. You catch the ball at 6 feet. How long is the ball in the air?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
You toss a ball from 5 feet. The ball's velocity is 30 feet per second. You catch the ball at 6 feet. How long is the ball in the air?
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h(t) = -16t^2 + 30t + 5
Solve for t at h(t) = 6 feet
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h(t) = -16t^2 + 30t + 5 = 6
-16t^2 + 30t - 1 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=836 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.0339479815749399, 1.84105201842506. Here's your graph:

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The 1st solution is at 6 ft on its way up.
The 2nd is the total time requested.
t =~ 1.841 seconds
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