SOLUTION: a man travels a total distance of 166km/hr. his average speed for the first 130km is xkm/hr and for the remaining journey , (x-25)km/hr. if the whole journey takes 3 hours and 15 m
Algebra.Com
Question 669481: a man travels a total distance of 166km/hr. his average speed for the first 130km is xkm/hr and for the remaining journey , (x-25)km/hr. if the whole journey takes 3 hours and 15 minutes , form an equation in terms of x.
solve this equation and hence find the time he would have saved if he maintains an average speed of xkm/hr throughout ?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a man travels a total distance of 166km/hr.
his average speed for the first 130km is xkm/hr and for the remaining journey, (x-25)km/hr.
if the whole journey takes 3 hours and 15 minutes, form an equation in terms of x.
:
Change 3 hrs 15 min to 3.25 hrs
:
Write a time equation; time = dist/speed
+ = 3.25
Multiply by x(x-25), results
130(x-25) + 36x = 3.25x(x-25)
:
130x - 3250 + 36x = 3.25x^2 - 81.25x
:
166x - 3250 = 3.25x^2 - 81.25x
A quadratic equation
3.25x^2 - 81.25x - 166x + 3250 = 0
:
3.25x^2 - 247.25x + 3250 = 0
:
solve this equation
Use the quadratic formula to find x;
a=3.25, b=-247.25, c=3250
Do this rather tedious math, the reasonable solution x ~ 59.18 km/h
;
find the time he would have saved if he maintains an average speed of xkm/hr throughout ?
:
= 2.8 hrs
3.25 - 2.8 = .45 hrs saved (.45*60 = 27 min)
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