SOLUTION: place the following equations in the standard form of a quadratic equation (ax^2+bx+c=0) a. 4/x^2+3/x-10=0 b. 6+4/x-1=5/x-3 c. 3.5x+4.6/x=1.2 please help

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Question 6686: place the following equations in the standard form of a quadratic equation (ax^2+bx+c=0)
a. 4/x^2+3/x-10=0
b. 6+4/x-1=5/x-3
c. 3.5x+4.6/x=1.2

please help
Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
I'll solve this one and you try other ones (same idea)
a. 4/x^2+3/x-10=0
use y instead of 1/x.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=169 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.25, -2. Here's your graph:


so, my solver says y=5/4, -2. That means that x=1/y = 4/5, -1/2.
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