SOLUTION: Find x-intercept(s)? 0 = 2x^2+4x-48

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Question 668322: Find x-intercept(s)?
0 = 2x^2+4x-48

Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
0 = 2x^2+4x-48
To find X intercept y=0






(x+6)(x-4)=0
x=-6 OR x=4
X Intercepts are -6 & 4



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