SOLUTION: I'm having a hard time with this problem. Please help! Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times wi

Question 66259: I'm having a hard time with this problem. Please help!
Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation. Use the vertex form to find the maximum area.
Answer:

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE MAXIMUNM AREA OF A RECTANGLE IS IN THE FORM OF A SQUARE THUS
X^2=400 SQUARE FEET
X=20 FEET FOR THE LENGTH & THE WIDTH
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