Hi,

Parabola: To graph, find x-intercepts,the Vertex, the line of symmertry and sketch it

f(x)= x^2 - 6x + 5, , x = 1 & x = 5 are the x-intercepts

f(x)= x^2 - 6x + 9 - 9 + 5 = (x-3)^2 - 4,  V(3,-4)  ||Putting into vertex form

the vertex form of a parabola:  where(h,k) is the vertex

The 2nd g(x) = x^2 + 4x + 4 - 4 + 13 = (x+2)^2 + 9 has no x-intercepts, 

V(-2,9)  and x = -2 is the line of symmetry. Note: both Open Upward, a>0  



 

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