SOLUTION: f(x)=x^2+6x+5 Find the x value of the vertex (turning point)

Question 64855: f(x)=x^2+6x+5
Find the x value of the vertex (turning point)
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
f(x)=x^2+6x+5
Find the x value of the vertex (turning point)
There are 2 ways to do this let me know if this isn't the way your teacher is doing it.
Because this is in f(x)=ax^2+bx+c form, I would use the formula to find the x-coordinate, then find f(-b/2a) to find the y-coordinate.
a=1, b=6

x=-3
y=

y=-4
The vertex is (-3,-4)
Happy Calculating!!!
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