SOLUTION: Find the reals of the solution: 2=y+6y^2

Question 643590: Find the reals of the solution: 2=y+6y^2
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

To solve a quadratic equation, you want one side to be zero. Subtracting 2 from each side:

Then we'll put the terms in "proper" order (highest exponent to lowest):

Now we factor:

Next we use the Zero Product Property which tells us that for any product, like this one, to be zero one of its factors must be zero. So:
or
Solving these...
or
or
Both of these are real numbers.
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