SOLUTION: what is the vertex of this graph y=x^2-11x+28

Question 639917: what is the vertex of this graph y=x^2-11x+28
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
a = 1, b = -11, c = 28

The vertex is (11/2, -9/4).
Here's how to graph:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=9 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 7, 4. Here's your graph:

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