SOLUTION: for what value of k does the equation kt^2 + 5t +2 = 0, have exactly one real solution for t?

Question 637675: for what value of k does the equation kt^2 + 5t +2 = 0, have exactly one real solution for t?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
for what value of k does the equation kt^2 + 5t +2 = 0, have exactly one real solution for t?
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Quadratic with a = k ; b = 5 and c = 2
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Discriminant:
b^2 -4ac = 5^2 -4k*2
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Solve:
5^2-4k*2 = 0
8k = 25
k = 25/8
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Cheers,
Stan H.
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