SOLUTION: I'm stumped. Thank you for your help. in a diving siblings showcase, 11-year old hannah takes off from a 24.61 foot platform with an initial velocity of 9.7 ft/sec at the same tim

Question 634986: I'm stumped. Thank you for your help.
in a diving siblings showcase, 11-year old hannah takes off from a 24.61 foot platform with an initial velocity of 9.7 ft/sec at the same time her brother tyler, who is 3.5 years older, takes off from a 32.81 foot platform with an initial velocity of 4.51 ft/sec. Who enters the water first? By how much? Round to the nearest hundredth.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
11-year old hannah takes off from a 24.61 foot platform with an initial velocity of 9.7 ft/sec
Hannah's height at time "t": ht) = -16t^2 + 9.7t + 24.61
solve h(t) = 0 for the time her height is zero.
Ans: t = 1.58 seconds
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at the same time her brother tyler, who is 3.5 years older, takes off from a 32.81 foot platform with an initial velocity of 4.51 ft/sec. Who enters the water first?
Brother's height at time "t": b(t) = -16t^2 + 4.51t + 32.81
Solve b(t) = 0 for the time his height is zero.
Ans: 1.58 seconds
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They hit the water at the same time.
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Cheers,
Stan H.

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