SOLUTION: solve
16x^4+47x^2=3
Algebra.Com
Question 633467: solve
16x^4+47x^2=3
Answer by dfrazzetto(283) (Show Source): You can put this solution on YOUR website!
16x^4+47x^2=3
16x^4 + 47x^2 - 3 = 0
(16x^2 -1)(x^2 + 3) = 0
16x^2 - 1 = 0; x^2 + 3 = 0
16x^2 = 1; x^2 = -3 (no solution, or radical 3*i, if using complex numbers)
x^2 = 1/16
x = +/- 1/4
RELATED QUESTIONS
solve... (answered by richwmiller,Alan3354)
Solve for x.
[(1/(2x)]^2 + [(2/(3x)]^2 =... (answered by ikleyn)
how can i solve this? I'm confused!
the sum of the degree measures of the three angles (answered by Alan3354)
C4. #16
Solve the equation
x^3-13x^2+47x-35=0 given that 1 is zero of... (answered by mathmate)
{{{x(2x^2+9x-56)(3x+10)=0}}}
I did this:
(2x^3+9x^2-56x)(3x+10)=0... (answered by Alan3354)
Solve.... (answered by vleith)
16x^2 – 25... (answered by solver91311,lenny460)
Solve.... (answered by MathLover1)
4.5
Solve the equation x^3 -13x^2 +47x-35=0 given that one is a zero of f(x)=x^3... (answered by Alan3354)