Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=16 is greater than zero. That means that there are two solutions: Quadratic expression Again, the answer is: 3, -1. Here's your graph: |
Hi,
f(x) = x^2-2x-3 Pt(0,-3) on this parabola
f(x) = (x-1)^2 -4
parabola Opening upward, V(1,-4), Line of Symmetry x = 1
0 = (x-1)^2 -4 , x-intercepts 1± 2, Pts (3,0) and (-1,0) on the curve
Sketch: