SOLUTION: find such that y=x^2-16x+c has exactly one real root
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Question 632507: find such that y=x^2-16x+c has exactly one real root
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find such that y=x^2-16x+c has exactly one real root
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a = 1 ; b = -16 ; c
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Solve: b^2 - 4*1*c = 0
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256 - 4c = 0
4c = 256
c = 64
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Cheers,
Stan H.
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