SOLUTION: Find the real zeros of the function P(x)=3(x+8)^2-(x+8)+4

SOLUTION: Find the real zeros of the function P(x)=3(x+8)^2-(x+8)+4

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Question 631668: Find the real zeros of the function P(x)=3(x+8)^2-(x+8)+4
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the real zeros of the function
P(x)=3(x+8)^2-(x+8)+4
**
P(x)=3(x+8)^2-(x+8)+4=0
let u=(x+8)
3u^2-u+4=0
b^2-4ac=1-4*3*4<0
no real solutions
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