SOLUTION: Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. f(x) = -2x^2 +

Question 625526: Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function.
f(x) = -2x^2 + 2x + 1
The x-coordinate of the vertex is:
(Type a simplified fraction)
The y-coordinate of the vertex is:
(Type a simplified fraction)
The equation of the line of symmetry is:
(Type an equation. Use integers or fractions for any numbers in the equation.)
The maximum/minimum of f(x) is:
(Type a simplified fraction.)
The value of f(1/2) = (3/2) is a
a) minimum
b) maximum

Any help is greatly appreciated.
Thank you!

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function.
f(x) = -2x^2 + 2x + 1
complete the square
f(x)= -2(x^2-x+1/4)+1+1/2
f(x)= -2(x-1/2)^2+3/2
This is an equation that opens downwards.(negative coefficient of leading term)
Its standard form of equation: y=-(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
..
The x-coordinate of the vertex is: 1/2
(Type a simplified fraction)
The y-coordinate of the vertex is: 3/2
(Type a simplified fraction)
The equation of the line of symmetry is x=1/2
(Type an equation. Use integers or fractions for any numbers in the equation.)
The maximum of f(x) is: 3/2
(Type a simplified fraction.)
The value of f(1/2) = (3/2) is a
b) maximum

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