SOLUTION: I am not certain how you get the answer for this, will you please show each step. The Problem: ar^2 - brs + ars - br^2 I worked some of the problem: ar^2 - brs + ars

SOLUTION: I am not certain how you get the answer for this, will you please show each step. The Problem: ar^2 - brs + ars - br^2 I worked some of the problem: ar^2 - brs + ars - br^2 =

Question 6255: I am not certain how you get the answer for this, will you please show each step.
The Problem: ar^2 - brs + ars - br^2
I worked some of the problem:
ar^2 - brs + ars - br^2 = ar^2 + ars - brs - br^2
= a(r^2 + rs) -b(rs - r^2)
= (r^2 + rs)(rs - r^2)<-did the"a" and "-b" cancel out?.

This is the textbook's anwser:
r(r + s)(a - b)
I am not understanding, please help.
tsj

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Factor: ar^2 - brs + ars - br^2
First, group the terms containing r^2 together and group the terms containing rs together.
(ar^2 - br^2) + (ars - brs) From the first group, factor the r^2 and from the second group, factor the rs.
r^2(a - b) + rs(a - b) Now factor the (a - b)
(a - b)(r^2 + rs) Finally, you can factor the r from the second group.
r(a - b)(r + s) and this is exactly equivalent to: r(r + s)(a - b)
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