SOLUTION: Find the vertex, line of symmetry,and the maximum or minimum value of f(x), graph the function. f(x)=(1)/(3)(x+1)^(2)+6

Question 625217: Find the vertex, line of symmetry,and the maximum or minimum value of f(x), graph the function.
f(x)=(1)/(3)(x+1)^(2)+6
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, line of symmetry,and the maximum or minimum value of f(x), graph the function.
f(x)=(1)/(3)(x+1)^(2)+6
Given equation is that of a parabola that opens upwards (has a minimum).
Its form of equation: A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
For given equation: (1/3)(x+1)^2+6
Vertex: (-1,6)
Line of symmetry: x=-1
minimum value=6
see graph below:

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