SOLUTION: find the vertex, line of symmetry, min or max and graph. f(x)=-2x^2+2x+1

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Question 624521: find the vertex, line of symmetry, min or max and graph. f(x)=-2x^2+2x+1
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
find the vertex, line of symmetry, min or max and graph.
f(x)= -2x^2+2x+1 |Completing square y = ax^2 + bx + c ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c
f(x)= -2(x-1/2)^2 + 1/2 +1
V(1/2,3/2,maximum -2<0, parabola opens downward along x =.5

the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry
The standard form is , where the focus is (h,k + p)
the vertex form of a Parabola opening right(a>0) or left(a<0),
where(h,k) is the vertex and y = k is the Line of Symmetry
The standard form is , where the focus is (h +p,k )

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