SOLUTION: 1) Find the vertex, the line of symmetry, and the max or min value of f(x). Graph the function.
f(x)=1/3(x+8)^2+9
The vertex is ?
The line of symmetry is ?
What is the max/min
Algebra.Com
Question 624098: 1) Find the vertex, the line of symmetry, and the max or min value of f(x). Graph the function.
f(x)=1/3(x+8)^2+9
The vertex is ?
The line of symmetry is ?
What is the max/min value of f(x)?
2) Find the x-intercepts and y-intercepts for f(x)
f(x)=x^2-6x+7
The x-intercept is?
The y-intercept is?
3)Give exact and approximate solutions to three decimal places.
(x-3)^2=12
What are the exact solutions?
What are the approximate solutions?
4) Find the vertex, the line of symmetry, and the max or min value of f(x). Graph the function.
f(x)= -x^2+12x+2
The vertex is?
The equation of the line of symmetry is?
The max/min of f(x) is?
The value of f(6)=38 is max or minimum?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ a(x\ -\ h)^2\ +\ k)
is the vertex form of a parabola with vertex at )
. Re-write your function as:
\ =\ \frac{1}{3}\left(x\ -\ (-8)\right)^2\ +\ 9)
and you can determine the coordinates of the vertex by inspection.
The line of symmetry is the vertical line through the vertex. The lead coefficient is positive, so the parabola opens upward and therefore the vertex is a minimum. The 
-coordinate of the vertex is the minimum value of the function.
John
My calculator said it, I believe it, that settles it
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