SOLUTION: I need to simplify this expression to the simplest form. {{{((x^2-9x+20)/(2x^2-7x-15))((2x^2-x-6)/(8+2x-x^2))}}}

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Question 623787: I need to simplify this expression to the simplest form.

Answer by math-vortex(648)   (Show Source): You can put this solution on YOUR website!
Hi, there---

Let's begin by trying to factor each of these trinomials. Typically, in textbook problems you 
will discover some common factors that you can then cancel out.



We need two numbers whose product is 20 and whose sum is -9; the numbers are -4 and -5.



The leading coefficient is 2 so we have an extra step to find the factors. 2x^2 factors as (x)(2x) 
and -15 factors as (-3)(5) or (3)(-5). The numbers are -5 and 3 because (2x)(-5)-(x)(3)=-7x.


Using similar reasoning,




Therefore,


Notice that (x-4), (2x+3), and (x-2) appear in the numerator and the denominator. We can 
"cancel these out" because a number divided by itself always equals 1. Any number multiply 
by 1 equals the same number.

Now we have 


Simplifying, we move the -1 outside the fraction.


Please email me if you have questions about this solution. I'll be happy to help you sort it out.

Ms.Figgy
math.in.the.vortex@gmail.com


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