SOLUTION: what is the vertex of x^2-4?! I think I did it wrong because once I plugged in my input values(-2,-1,0,1,2) I got (-2,-16) (-1,-4) (0,0) (1,-4) (2,-16) so once I graphed it I got

Question 619066: what is the vertex of x^2-4?!
I think I did it wrong because once I plugged in my input values(-2,-1,0,1,2) I got (-2,-16) (-1,-4) (0,0) (1,-4) (2,-16) so once I graphed it I got a downward parabola, and isnt it supposed to be upward since my x^2 is positive?! Please help me figure this out! Also, once for the the vertex points I did (x+2)=0 and (x-2)=0 to solve for x then I simply plugged it in to find y; however, once I did that my vertex points turned out to be (-2,16) (2,16)! This shouldnt be right since the vertex is the highest and lowest value! Please help... Thank you!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm not sure how you're getting those output values. When x = -2, y is...

y = x^2 - 4

y = (-2)^2 - 4

y = 4 - 4

y = 0

So when x = -2, y = 0. So we have the point (-2,0)

Hopefully that will get you on the right track. If not, please let me know.
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