SOLUTION: A) Build a pattern using tiles for y=x^2-4x+3
B) Show how your pattern would look for x= -2,-1,0,1,2 (do I simply plug these number in the quadratic equation?!)
C) Find the y-int
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Question 618833: A) Build a pattern using tiles for y=x^2-4x+3
B) Show how your pattern would look for x= -2,-1,0,1,2 (do I simply plug these number in the quadratic equation?!)
C) Find the y-intercept and the x- intercept (if any), the turning point (vertex) and the range.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I'm not sure what sort of new math folderol "build a pattern using tiles" is supposed to be, but yes, plug each of the given 
values into your given function and report the function value for each.
The 
-intercept is the point with a zero -coordinate and the value of the function when 
for a -coordinate.
Set the function equal to zero and then solve the resulting quadratic equation for the two roots. The -intercepts will be the two points where the -coordinate is equal to one or the other of the roots and the -coordinate is zero.
Find the -coordinate of the vertex using the formula 
where 
is the lead coefficient and 
is the coefficient on the first degree term, as in \ =\ ax^2\ +\ bx\ +\ c)
The -coordinate of the vertex is the value of the function at the -coordinate of the vertex. Hint: You have already calculated it in part B of the problem.
Since the lead coefficient is positive, the parabola opens upward. Hence the vertex is a minimum of the function. Therefore the lower limit of the range is the value of the function at the vertex, i.e., the number you calculated in the previous step. Since this is a parabola and the domain has not been otherwise restricted, there is no upper bound to the range.
John
My calculator said it, I believe it, that settles it
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