SOLUTION: Solve the following quadratic equations by using quadratic formula.
2.1y^2-3.5y=4
a(a+2)=-1
6x^2+5x-4=3x-2
4x^2-14x-27=3
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Question 61750This question is from textbook college algebra
: Solve the following quadratic equations by using quadratic formula.
2.1y^2-3.5y=4
a(a+2)=-1
6x^2+5x-4=3x-2
4x^2-14x-27=3
This question is from textbook college algebra
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve the following quadratic equations by using quadratic formula.
2.1y^2 - 3.5y = 4
:
2.1y^2 - 3.5y - 4 = 0
I assume you know that the quadratic formula is, here is the first one step-by=step:
a = 2.1; b = -3.5; c = -4
:
y = +2.446
and
y = -.779
:
:
a(a+2) = -1
a^2 + 2a + 1 = 0;
a = 1; b = 2; c = 1,
Complete this like we did above, you will find that it is easy, everything inside the radical cancels out.
a = -1
:
:
Substitute for a,b,c like we did in the 1st one
6x^2 + 5x -4 = 3x - 2
6x^2 + 5x - 3x - 4 + 2 = 0
6x^2 + 2x - 2 = 0
a = 6; b = 2; c = -2
:
:
4x^2 - 14x - 27 = 3
4x^2 - 14x - 27 - 3 = 0
4x^2 - 14x - 30 = 0
a = 4; b =-14; c = -30
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