SOLUTION: Find the two values of "b" for which the quadratic equation 4x^2+bx+49=0 has two real solutions b=( ) b= ( )

Question 617410: Find the two values of "b" for which the quadratic equation 4x^2+bx+49=0 has two real solutions
b=( ) b= ( )
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
A quadratic equation will have two real solutions if its discriminant, , is positive. IOW:

Inserting our values for a and c:

Since , b can be any number greater than 28 or less than -28! As long as b > 28 or b < -28, there will be two real solutions to your equation. Just pick any two such numbers.

There not just two possible values for b as the problem seems to suggest.

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