SOLUTION: How do I finish this? x^2+8x-3=0 x^2+8x=3 x^2+8x+64/4=3/1+64/4=12/4+64/4=76/4 x^2+8x+64/4=76/4 (x+8/2)^2=76/4 x+8/2=+ or - the square root of 76/4........ I got stuck right

Algebra.Com
Question 61604: How do I finish this? x^2+8x-3=0
x^2+8x=3
x^2+8x+64/4=3/1+64/4=12/4+64/4=76/4
x^2+8x+64/4=76/4
(x+8/2)^2=76/4
x+8/2=+ or - the square root of 76/4........
I got stuck right here.

Answer by rchill(405)   (Show Source): You can put this solution on YOUR website!
can be rewritten as and that can be rewritten as . That reduces to , which reduces further to .
RELATED QUESTIONS

Factor {{{8x^3+343}}} Factor... (answered by solver91311)
(x-4)^2=64 (answered by ewatrrr)
solve by factor completing the square x^2 - 8x+10=0 x^2 - 8x= -10 (8/2)^2= 64/4= 16 (answered by jim_thompson5910)
4(x+1)^2=64 (answered by Fombitz)
4(X+1)^2=64 (answered by srinivas.g,MathLover1)
1. 2x^2+10x+12 Factor completely 2.x^2+8x=-16 3.x^2-16=0 4. x^2-16x=-64 5. (answered by ankor@dixie-net.com)
My book says the answer is -5 and -3, where am I missing it? {{{x^2-8x-15=0}}}... (answered by nerdybill)
My book says the answer is -5 and -3, where am I missing it? {{{x^2-8x-15=0}}}... (answered by ankor@dixie-net.com,Edwin McCravy)
x^3/2=64 cubed root of 64 is... (answered by Fombitz)