SOLUTION: solve 2x^2-3x=7 using quadratic function and rounding to the nearest tenth

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Question 613578: solve 2x^2-3x=7 using quadratic function and rounding to the nearest tenth
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=65 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.76556443707464, -1.26556443707464. Here's your graph:
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