SOLUTION: A certain population of a city increases according to the model P(t) = 250e<sup>0.47t</sup> with t=0 corresponding to the year 1992, where t is in years. Which of thr followi

Question 612465: A certain population of a city increases according to the model
P(t) = 250e^0.47t
with t=0 corresponding to the year 1992, where t is in years.
Which of thr following equations expresses the population present
in the year 2000?
A. P(2000) = 250e^0.47(2000)
B. P(1992) = 250e^0.47(1992)
C. P(6) = 250e^0.47(6)
D. P(8) = 250e^0.47(8)
Hope somebody can help.
Found 4 solutions by solver91311, ewatrrr, G8TORS, Edwin McCravy:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

For the year 1992, since corresponds to the year 1992, your function would be . Then consider that 2000 minus 1992 equals 8.

John

My calculator said it, I believe it, that settles it

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi, re TY, Yes, D is the correct choice.
with t=0 corresponding to the year 1992
population present in the year 2000: (2000-1992 = 8)
Answer by G8TORS(10)   (Show Source): You can put this solution on YOUR website!
D. =
model is for "populatin increase" 1992 to 2000 is 8 yrs. Nothing else makes sense.
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!

P(t) = 250e^0.47t Since t=0 corresponds to the year 1992, then t=1 corresponds to the year 1993, t=2 corresponds to the year 1994, t=3 corresponds to the year 1995, t=4 corresponds to the year 1996, t=5 corresponds to the year 1997, t=6 corresponds to the year 1998, t=7 corresponds to the year 1999, t=8 corresponds to the year 2000, So since t=8 is the value of t that corresponds to 2000, you take out both the t's in P(t) = 250e^0.47t and put (8) in their place. So the answer is P(8) = 250e^0.47(8) Edwin

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