SOLUTION: a ball thrown from the height of 3m with the speed of 4m/s. find quadretic equation.i got answer -9.8t^2+4t+3but i donot understand how -9.8

Question 612304: a ball thrown from the height of 3m with the speed of 4m/s. find quadretic equation.i got answer -9.8t^2+4t+3but i donot understand how -9.8
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The "acceleration of gravity" is
9.8 meters/sec^2
since, the force is downward it will be negative.
.
The general form of the equation of motion is:
(1/2)gt^2 + vt + h
where
g is gravity (m/sec^2)
t is time (sec)
v is initial velocity
h is initial height
.
your equation should be:
-(1/2)gt^2 + vt + h
-(1/2)9.8t^2+4t+3
-4.9t^2+4t+3

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