SOLUTION: how do I rewrite the quadratic equation x^2+6x-8 in vertex form?

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Question 611378: how do I rewrite the quadratic equation x^2+6x-8 in vertex form?
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


What equation? Your quadratic trinomial isn't equal to anything, so you don't have an equation. Quadratic equation is the wrong terminology anyway. You want to talk about a quadratic function if you want to convert to vertex form.

Try this:



Now, complete the square on the right and then collect terms to result in a function that has the following pattern:



which is a parabola with a vertical axis of symmetry and a vertex of (h,k). The parabola opens upward if , downward otherwise. is the distance from the vertex to the focus of the parabola and is the distance from the vertex to the directrix.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
how do I rewrite the quadratic equation x^2+6x-8 in vertex form?
-------
Complete the square:
x^2+6x-8 = y
x^2+6x+3^2 = y+8+3^2
----
(x+3)^2 = y+17
----------------------
Vertex: (-3,-17)
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Cheers,
Stan H.
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