SOLUTION: The length of a rectangle is 2 times its width. The area of the rectangle is 72 square inches. Find the dimensions of the rectangle. How would I solve this by factoring

Algebra.Com
Question 610508: The length of a rectangle is 2 times its width. The area of the rectangle is 72
square inches. Find the dimensions of the rectangle.
How would I solve this by factoring?

Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
First you need an equation. The factoring comes later.

The equation we will use is the equation for area of a rectangle:
A = l*w
We know the area. We do not know the length or width so we will need to write expressions for them. In general, it is helpful if you make the variable represent the lowest unknown number. In this case it would be the width. So we will have...
x = width of the rectangle
Since the length is 2 times the width and since the width is x, this makes...
2*x = length of the rectangle.

Now, in the equation for area, we substitute in for A, l and w:
(72) = (2*x)*(x)

Now that we have an equation we can start solving the problem. As usual, you start by simplifying each side:

This is a quadratic equation (because of the term). So we want one side to be zero. Subtractin 72 from each side we get:

Next we factor (or use the Quadratic Formula). You were told to factor so that is what we will do. When factoring, alwyas start with the GCF. Here the GCF is 2:

Next we want to factor . Since this is a difference of squares. A difference of squares factors according to the pattern: . Using this pattern to factor we get:

Now that the right side is fully factored, we use the Zero Product property which tells us that any product can zero only if one (or more) of the factors is zero. The factor of 2 cannot be zero but the other two factors could. So:
x+6 = 0 or x-6 = 0
Solving each of these we get:
x = -6 or x = 6

Remembering that x represents the width of the rectangle and knowing that widths cannot be negative, we discard the negative solution. So the width of the rectangle is 6. For the length we have to remember that it was 2*x. So the length is 2*6 or 12. (Note: It is a good habit to write down what you variable represents, like we did for the width above, and to write down other expressions you may have used, like we did for the length above. This way you can just look back to see how to user the value you found for "x" to determine what the answer(s) are to the problem.

RELATED QUESTIONS

The length of a rectangle is 4 times its width. The area of the rectangle is 144 square... (answered by ewatrrr)
The length of a rectangle is 6 inches less than three times its width. Find the... (answered by RAY100)
A rectangle has an area of 900 square inches. The length of the rectangle is 2.25 times... (answered by troyapplehelen)
A rectangle has an area of 432 square inches. The width of the rectangle is 3/4 times its (answered by mananth)
a rectangle has an area of 432 square inches. The width of the rectangle is 3/4 times its (answered by algebrahouse.com)
the length of a rectangle is 31 centimeters less than five times its width. the area is... (answered by mananth)
The length of a rectangle is 6 inches more than its width. The area of the rectangle... (answered by checkley79)
The length of a rectangle is 7 foot less than 2 times the width. Find the dimensions of... (answered by unlockmath)
The length of a rectangle is twice that of its width. If the area of the rectangle is 72 (answered by josgarithmetic)