SOLUTION: find the vertex of the following: y=(x-5)^2 y=(x+3)^2 y=(x-1)^2 y=x^2+8 y=x^2-5 y=x^2+2

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Question 608521: find the vertex of the following:
y=(x-5)^2
y=(x+3)^2
y=(x-1)^2
y=x^2+8
y=x^2-5
y=x^2+2

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Note: the vertex form of a parabola opening up or down, where(h,k) is the vertex
find the vertex of the following:
y=(x-5)^2
y=(x+3)^2
y=(x-1)^2
y=x^2+8
y=x^2-5
y=x^2+2
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