SOLUTION: Can you help me find the x-intercepts??
y=x^2+6x+8 and
y=x^2-2x+4
Thanks for your help!
CH
Algebra.Com
Question 60788: Can you help me find the x-intercepts??
y=x^2+6x+8 and
y=x^2-2x+4
Thanks for your help!
CH
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Hi CH
find the x-intercepts??
y=x^2+6x+8 and
Let y=0 and solve for x.
0=x^2+6x+8 Factor
0=(x___)(x___) the blank gets filled with two numbers that multiply to get 8 and add to get 6. 2*4=8 and 2+4=6
0=(x+2)(x+4) Let each parentheses=0
x+2=0 and x+4=0
x=-2 and x=-4
The x-intercepts are (-2,0) and (-4,0)
:
y=x^2-2x+4
This has no x-intercepts. It's not factorable. If you're familiar with the discriminant:, you can tell if a quadratic equation has no x-intercepts if the discriminant is negative.
There are no x-intercepts.
Happy Calculating!!!
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