I am having a REALLY hard time with this: Complete the given table of values and graph the equation. y=x^2-5x+4 The given table has nothing under y. Under x looking downward is 0,1,2,3,4. Your help would be greatly appreciated! Thanks~ ac x y 0 ? 1 ? 2 ? 3 ? 4 ? First substitute x = 0 y = x² - 5x + 4 y = 0² - 5(0) + 4 y = 0 - 0 + 4 y = 4 so we write 4 in the y column next to 0 in the x column, and we have x y 0 4 1 ? 2 ? 3 ? 4 ? Next substitute x = 1 y = x² - 5x + 4 y = 1² - 5(1) + 4 y = 1 - 5 + 4 y = 0 so we write 0 in the y column next to 1 in the x column, and we have x y 0 4 1 0 2 ? 3 ? 4 ? Next substitute x = 2 y = x² - 5x + 4 y = 2² - 5(2) + 4 y = 4 - 10 + 4 y = -2 so we write -2 in the y column next to 2 in the x column, and we have x y 0 4 1 0 2 -2 3 ? 4 ? Next substitute x = 3 y = x² - 5x + 4 y = 3² - 5(3) + 4 y = 9 - 15 + 4 y = -2 so we write -2 in the y column next to 3 in the x column, and we have x y 0 4 1 0 2 -2 3 -2 4 ? Next substitute x = 4 y = x² - 5x + 4 y = 4² - 5(4) + 4 y = 16 - 20 + 4 y = 0 so we write 0 in the y column next to 4 in the x column, and we have x y 0 4 1 0 2 -2 3 -2 4 0 Now we plot the four points (0,4), (1,0), (2,-2), (3,-2), and (4,0)Then we draw a smooth curve through those five points: Edwin