SOLUTION: How do you solve for a vertex when B is not given. {{{y=X^2+5}}} i know how to do it when it is ax^2+bx+c, but i dont know what to do when its just ax^2+c

Question 606647: How do you solve for a vertex when B is not given. i know how to do it when it is ax^2+bx+c, but i dont know what to do when its just ax^2+c
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Note: the vertex form of a parabola opening up or down,  where(h,k) is the vertex.

 tells us "h" = 0

Vertex is Pt(0,5)



 

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