SOLUTION: (8t-3)^2=0 (2x-1)^2=8 x^2-4x+4=49

Algebra.Com
Question 60623This question is from textbook college algebra
: (8t-3)^2=0
(2x-1)^2=8
x^2-4x+4=49
This question is from textbook college algebra

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
(8T-3)^2=0
64T^2-48T+9=0
-----------------------------
(2X-1)^2=8
4X^2-4X+1=8
4X^2-4X-7=0
--------------------------------
X^2-4X+4=49
X^2-4X+4-49=0
X62-4X-45=0

RELATED QUESTIONS

x^2-4x+4=49 (3x-6)^2=4x^2... (answered by uma)
1) 2(x-1)=5/2 2)... (answered by lynnlo)
(x-3)^2+(x+2)^2=17 (x-3)(x-3) + (x+2)(x+2)=17 (x^2-6x+9) + (x^2+4x+4) =17 x^2 - 6x... (answered by eperette)
x^3-2x^2+4x-8=0:... (answered by Boreal)
simplify. {{{ (6x-3)/(4x+8)}}} * {{{(2x+4)/(4x^2-1)... (answered by nabla,shahid)
2t^2-8t=0 (answered by edjones)
Simplifying: 2(2x+-4)+-3(4x+-1)+2(x+3)=0 (answered by mohd18)
{{{ 8 (x+1)(x-3)/x^2-x-12 × x-4/4x^2-12x ÷ (x+1)(x+2)/2x+6... (answered by ikleyn)
4x-4x^1/2=3 2x^2/3-x^1/3=0... (answered by ewatrrr)