SOLUTION: How do you solve 4x2=96, x2-20=0, and 5(x-2)2=125
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Question 60104: How do you solve 4x2=96, x2-20=0, and 5(x-2)2=125
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
How do you solve
x=+\-
x=+\-
x=+\-
:
x=+\-
x=+\-
:
x-2=+\-5
x=2+\-5
x=2-5 and x=2+5
x=-3 and x=7
Happy Calculating!!!
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