SOLUTION: i can never figure out word problems can you please help. thank you in advance 108. Boxing match. A boxing ring is in the shape of a square, 20 feet on each side. How far

Question 59821: i can never figure out word problems can you please help. thank you in advance
108. Boxing match. A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE DIAGONAL OF A SQUARE 20 FOOT RING IS SOLVED BY THE FORMULA A^2+B^2=C^2 WHERE THE A & B SIDES ARE 20 FEET. THUS THE DIAGONAL (C) IS
20^2+20^2=C^2
400+400=C^2
800=C^2
C=SQRT800
C=28.28 FEET IS THE DIAGONAL ACROSS THE RING

RELATED QUESTIONS
Please help to solve this Radical Expressions and Equations word problem. Here is the... (answered by Roseghanezadeh)

I asked a question about a boxing ring yesterday and have studied up and down on the... (answered by longjonsilver)

I really need your help in solving this problem. I appreciate your time and efforts. Have (answered by TimothyLamb)

Problem A boxing ring is in the shape of a square 20ft on each side. How far apart... (answered by stanbon)

Hi there, my question is this: A square boxing ring is 20ftx20ftx20ftx20ft, how far... (answered by longjonsilver)

A boxing ring is in the shape of a square, 20 ft on each side. How far apart are the... (answered by Nate)

A boxing ring is in the shape of a square with 20 ft. on each side. How far apart are... (answered by checkley71)

A boxing ring is in the shape of a square, 20 ft on each. How far apart are the fighters... (answered by checkley77)

a boxing ring is in the shape of a square,20 ft on each side. how far apart are the... (answered by stanbon)