SOLUTION: a ball is thrown in the air. the relationship between the time the ball is in the Air in seconds (t) and the height of the ball in the feet above the ground (h) is represented by h
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Question 596989: a ball is thrown in the air. the relationship between the time the ball is in the Air in seconds (t) and the height of the ball in the feet above the ground (h) is represented by h=-16t^2 + 11t+5?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your equation is only accurate to the extent that the ball is released when it is 5 feet above the ground and it is thrown upward with a vertical initial velocity component of 11 feet per second. In general, a projectile propelled upward at an initial velocity of 
distance units per time unit from an initial height of 
distance units above the surface of a celestial body with a near-surface gravitational acceleration of 
distance units per time unit per time unit is:
\ =\ -\frac{1}{2}g_it^2\ +\ v_ot\ +\ h_o)
Other than that, what is it you wanted to know?
John
My calculator said it, I believe it, that settles it
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