SOLUTION: a rocket is launched from an 18-foot cliff with an initial velocity of 80 feet per second. the height above the ground of the rocket t seconds after launch is given by the equation

Question 593997: a rocket is launched from an 18-foot cliff with an initial velocity of 80 feet per second. the height above the ground of the rocket t seconds after launch is given by the equation h= -16^2+80t+18. hjow long after the rocket is launched will it hit the ground? round your answer to the nearest tenth.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a rocket is launched from an 18-foot cliff with an initial velocity of 80 feet per second. the height above the ground of the rocket t seconds after launch is given by the equation h= -16^2+80t+18. hjow long after the rocket is launched will it hit the ground? round your answer to the nearest tenth.
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It's when h = 0.
h= -16^2+80t+18 = 0
Solve for t.
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Why is this called a rocket? It has no engine, doesn't accelerate.
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