SOLUTION: If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 � 10t + 230, where t is in seconds, and height i

Question 593595: If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 � 10t + 230, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth�s place; include units in your answer.
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
h(t) = -9.8t^2 � 10t + 230,
When it hits the ground, h(t) = 0, therefore
-9.8t^2 � 10t + 230 = 0
Use the quadratic formula to find t

In this problem: x=t; a=-9.8; b=-10; c=230

:

I'll let you do the rather tedious math here, you should get a positive solution of about 4.36 seconds
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 � 10t + 230, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth�s place; include units in your answer.
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The other tutor got the right answer, ~ 4.36 seconds, but
if you're on Earth, the equation is
h(t) = -4.9t^2 � 10t + 230

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