SOLUTION: Suppose a particular star is projected from an aerial firework at a stating height of 520 ft with an initial upward velocity off 72ft/s. How long will it take for the star to reach

Question 584986: Suppose a particular star is projected from an aerial firework at a stating height of 520 ft with an initial upward velocity off 72ft/s. How long will it take for the star to reach its maximum height? How far will it be?
The equation is h= -16t^2+ 72t +520
also, describe the importance of quadratics (one paragraph) and how quadratics helps people to understand something in the real world
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Suppose a particular star is projected from an aerial firework at a stating height of 520 ft with an initial upward velocity off 72ft/s.
How long will it take for the star to reach its maximum height?
:
The equation is h= -16t^2+ 72t + 520
Max height occurs at the axis of symmetry; use the formula x = -b/(2a)
t =
t =
t = +2.25 secs to reach max height
:
" How far will it be?" Assume you mean how high.
Replace t with 2.25 sec in the original equation
h = -16(2.25^2)+ 72(2.25) + 520
h = -16(5.0625)+ 162 + 520
h = -81 + 162 + 520
h = 601 ft is the max height
:
describe the importance of quadratics (one paragraph) and how quadratics helps people to understand something in the real world
:
Many things that happen in the world are not linear, quadratic equations help us calculate phenomena which are not linear like the above example
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