SOLUTION: Find the maximum of P(x) = -x^2 + 8x + 1.

Question 58378This question is from textbook Applied College Algebra
: Find the maximum of P(x) = -x^2 + 8x + 1. This question is from textbook Applied College Algebra

Answer by babynarah2007(12) (Show Source): You can put this solution on YOUR website!
Find the maximum of P(x) = -x^2 + 8x + 1.
In general quadratic fuction F(x)= ax^2 + bx + C is a parabola,
we need to find the line of symmetry
p(x)= -x^2 + 8x + 1
Note:(in this case, the graph will open down when the value of A is negative units or sign) A= -1 , b= 8 , c= 1

the X coordinate of the vertex is given by (-b/2a)= -(+8)/2(-1)= 4
the y coordinate of the vertex is given by
p(-b/2a)or p(4)= -x^2+8x+1
= -(4)^2+8(4)+1
= -16 + 32 + 1
= 17
Ans. the maxium of P(X) is 17
Note; this kind of problem you can solve by Quadratic fuction Form or Symmetry Form or Factor Form.
Best luck with your home work
Honestly solved by babynarah2007@yahoo.com
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