SOLUTION: t^2+1=13/6t
Algebra.Com
Question 57581: t^2+1=13/6t
Answer by terbear1963(43) (Show Source): You can put this solution on YOUR website!
FIRST MULTIPLY EACH SIDE BY 6 TO GET RID OF YOUR MENACING FRACTIONS!!! 6(T^2+1)=(13/6T)6 ---> 6T^2+6=13T ---> 6T^2-13T+6=0 ---> (3T-2)(2T-3)=0 ---> 3T-2=0 AND 2T-3=0 ---> T=2/3 AND T=3/2 I HOPE THIS HELPS YOU!? YOUR MATH FRIEND , TERRY ( CATS7051@YAHOO.COM )
RELATED QUESTIONS
(6t^2-t-4)(8t^2+6t-1) (answered by Cromlix)
2(6t+1)-4(t-1)=0 (answered by ReadingBoosters)
t^2-6t-27 (answered by algebrahouse.com)
t(5t^2+6t) (answered by rfer)
Solve
t^2 + 3 =... (answered by unlockmath,solver91311)
Solve for t.... (answered by rfer)
Solve by factoring:
6t^2 – t – 1 = 0
(answered by algebrahouse.com)
5/6t+4=2-1/6t (answered by Alwayscheerful)