SOLUTION: m^2+m-62=-6

Question 573158: m^2+m-62=-6
Answer by mathsmiles(68) (Show Source): You can put this solution on YOUR website!
m^2 + m -62 = -6

First thing we want to do is get this into standard format:
m^2 + m -62 = -6 Add 6 to both sides:
m^2 + m -56 = 0
(m - )(m + ) = 0
We're looking for two factors of 56 that are only different by one.
7 x 8 = 56
(m + 8)(m - 7) = 0 FOIL: m^2 - 7m + 8m -56 = m^2 + m - 56 Yay!

(m + 8) = 0
m = -8
(m - 7) = 0
m = 7

Checking:
(-8)^2 + (-8) - 62 = -6
64 - 8 - 62 = -6
56-62 = -6
-6 = -6 Correct!
(7)^2 + (7) - 62 = -6
49 + 7 - 62 = -6
56 -62 = -6
-6 = -6 Correct!

RELATED QUESTIONS
M/m^2-4+2/m^2+5m+6-3m/m^2+m-6 (answered by ikleyn)

-2=m+6 (answered by jim_thompson5910)

7[3m - (m + 2)] > -6(m -... (answered by stanbon)

9(m+2)=-6(m+7) (answered by jim_thompson5910)

(m^2n)^-2/m^-2n^6 (answered by ankor@dixie-net.com)

m/4-1/2=m/6+5 (answered by mareebsiddiqui)

9m-3(m+6)=2(m+1) (answered by Fombitz)

If m<4=122 what is m<8 m<5 m<2 m<1 m<6... (answered by ikleyn)

m^2-m=6 =m^2-m-6=0 I need details on the solution... (answered by jim_thompson5910)