SOLUTION: my homework question reads:
an object is thrown upward from the top of a 256ft tower at a velocity of 96ft/sec. Find the height after 3 seconds.
I know I need to use the quadra
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Question 571016: my homework question reads:
an object is thrown upward from the top of a 256ft tower at a velocity of 96ft/sec. Find the height after 3 seconds.
I know I need to use the quadratic equation, but I don't know what to do next.
3t=-16t^2+96t+256
16t^2-93t-256=0
Thanks for your help!
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
According to Physics, the height as a function of time in seconds should be
After 3 seconds, the object's height is
The quadratic function has a maximum and its graph (h versus t) is a parabola.
To figure out when it reaches its highest altitude, find the axis of symmetry of the parabola:
-->
So the object reaches its maximum height at 9 seconds.
That height is
To find out when it hits the ground (), you solve the quadratic equation
or the equivalent
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