SOLUTION: Solve the equation by factoring. (2x/x+3)+(5/x)-4=(18/x^2+3x) ----------- ----------- -------- I have gotten this far with the problem.... LCM = X(x+3) thus I have 2x^2+5x+15

Question 570645: Solve the equation by factoring.
(2x/x+3)+(5/x)-4=(18/x^2+3x)
--------------------------------
I have gotten this far with the problem....
LCM = X(x+3) thus I have 2x^2+5x+15-4x^2-12=18--->-2x^2+5x+3=18--->-2x^2+5x-15=0

I think my problem is the (-2x^2) which I got from 2x^2-4x^2 and the (-4x^2) is from multiplying the LCM (x(x+3))to -4.
Could you show me where my error is?
Thank you
Kenneth
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve:
Simplify. The LCD is
so we have:
Subtract 18 from both sides.
Multiply through by -1 to get:
Factor.
Apply the zero product rule:
or so...
or
Notice: The left side becomes...
which, when simplified becomes:
=
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