SOLUTION: I need help on this one please
f(x)= 1/4(x+9)^2+1
I need to find out what the vertex is____
I need to find out what the line of symmentry is _____
I need to find out what i
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Question 564945: I need help on this one please
f(x)= 1/4(x+9)^2+1
I need to find out what the vertex is____
I need to find out what the line of symmentry is _____
I need to find out what is the max/min value of fx is _________
Found 2 solutions by Alan3354, htmentor:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
f(x)= 1/4(x+9)^2+1
------------
It's in standard form, so the LOS is x = -9
The vertex is (-9,1), taken from the standard form.
The minimum is the vertex.
I need to find out what the vertex is____
I need to find out what the line of symmentry is _____
I need to find out what is the max/min value of fx is _________
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
I need help on this one please
f(x)= 1/4(x+9)^2+1
I need to find out what the vertex is____
I need to find out what the line of symmentry is _____
I need to find out what is the max/min value of fx is _________
==========================================
f(x)= 1/4(x+9)^2+1
Since this parabola opens upward, the vertex will be a minimum value
The function has a minimum at x = -9
f(-9) = 1
So the vertex is (-9,1)
The line of symmetry runs parallel to the y-axis and goes through the vertex (-9,1).
Therefore the line of symmetry is x = -9
The graph is below:
The minimum value is the vertex (-9,1)
The maximum value is
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